Question

a point charge q is kept on equatorial position of an electric dipole moment p at distance r as shown in the figure electric potential at the centre of dipole is
.p/4πE0r2
.zero
.p/4πE0r
.p/4πE0r + p/4πE0r​

Answer 1

Explanation:

Let AB be an electric dipole consisting of +q nd -q charges separated by distance of 2l. A point P lies on the neutral axis (or equatorial or transverse position) at a distance r from the centre O of dipole, where we have to determine the potential:

AP=BP=

l

2

+r

2

Potential at P due to +q charge will be

V

1

=

4πεk

1

×

AP

q

=

4πε

0

k

l

2

+r

2

q

Similarly, potential at P due -q charge will be:

v

2

=

4πε

0

k

1

[

BP

−q

]=

4πε

0

k

l

2

+l

2

−q

Where k = dielectric constant of medium.

Hence resultant potential at point P,

V=V

1

+V

2

V=0