Physics, asked by vanijain9356, 10 months ago

A point charge Q is placed at the origin. Find the electrostatic energy stored outside the sphere of radius R centred at the origin.

Answers

Answered by madhusingh2033
1

Answer:

the electrostatic charge will be zero

Answered by shilpa85475
0

Electrostatic energy (E) = Q2/8π ∈0 R

Explanation:

From the given,

Charge on the sphere = Q

Radius of the sphere = R

Capacitance of the sphere, \mathrm{C}=4 \pi \in 0 \mathrm{R}

The Energy of the Capacitor (E) = 1 / 2 \mathrm{CV} 2

Where C = Capacitance of the circuit

V = Potential difference / voltage across the capacitor

∈0 = dielectric constant of the material used between the plates of the capacitor.

By substituting the values  

=1/2 X 4π∈0 R X Q2/ (4π∈0 R) 2

Hence,

Electrostatic energy (E) = Q2/8π ∈0 R

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