Physics, asked by honey19200, 10 months ago

A point charge q is placed at x=-1m. The potential at x=2m will be​

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Answered by mufeedhapc256
2

Answer:

30V

Explanation:

potential due to a point charge,

V=KQ/r

(where, k=1/4π£•

Q=charge=10nC=10×10^-9C

r=distance between charge and point)

  • therefore,

V=9×10^9×10×10^-9/3

=30V

hope this helps..!!

Answered by amitnrw
0

The potential at x=2m will be​ 30 V

Explanation:

the electric potential (V) produced by a point charge with a charge of magnitude q , at a point a distance d away from the point charge, is given by the equation:

V = kq/d

unit Charge is at   - 1 m

q = 10nC  at   2 m

d = 2 -(-1) = 3 m

k = 9 * 10⁹ Nm²C⁻²

q =  10nC = 10 * 10⁻⁹ C

V = kq/d   =   9 * 10⁹  10 * 10⁻⁹/3

=> V = 30

Potential at x=  2 will be 30 V

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