A point charge q is placed at x=-1m. The potential at x=2m will be
Answers
Answer:
30V
Explanation:
potential due to a point charge,
V=KQ/r
(where, k=1/4π£•
Q=charge=10nC=10×10^-9C
r=distance between charge and point)
- therefore,
V=9×10^9×10×10^-9/3
=30V
hope this helps..!!
The potential at x=2m will be 30 V
Explanation:
the electric potential (V) produced by a point charge with a charge of magnitude q , at a point a distance d away from the point charge, is given by the equation:
V = kq/d
unit Charge is at - 1 m
q = 10nC at 2 m
d = 2 -(-1) = 3 m
k = 9 * 10⁹ Nm²C⁻²
q = 10nC = 10 * 10⁻⁹ C
V = kq/d = 9 * 10⁹ 10 * 10⁻⁹/3
=> V = 30
Potential at x= 2 will be 30 V
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