Question

A point E is taken on the side BC of a parallelogram ABCD. AE and DC are produced to meet at F. Prove that ar(triangle ADF)=ar(quadrilateral ABFC) Note :- E is not the midpoint of BC

Answer 1

ar(ADF)=ar(ADC)+ar(ACF)
ADC=ABC
ACF=BFC
ABFC=ABC+BCF

HENCE PROVED