A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the point P on the tower and the top T of the tower at 30° and 50° respectively calculate to 35.7
a) /PT/
b) the distance between H and the top of the tower
c) the position H if the angle of H from the top of the tower is 40°
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Answer:
Let AB be the height of the tower and C be the point.
In right △ABC,
tan30
o
=
BC
AB
AB=BCtan30
o
AB=
3
20
=11.56 m
Therefore, the height of the tower is 11.56 m.
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