Question

A point is placed in air
a distance of 3m
from concave refracting surface of material of
refractive index 1.5. Find the position of image
if the radius of curvature of spherical
mirror
is 5m.​

Answer 1

Step-by-step explanation:

ANSWER

Given object distance u=40 cm, radius of curvature R=20 cm

refractive index n

2

=1.5 and n

1

=1

Now making use of the relation

v

n

2

−

u

n

1

=

R

n

2

−n

1

v

n

2

=

R

n

2

−n

1

+

u

n

1

v

n

2

=

−20

1.5−1

−

−40

1

v

n

2

=

−40

2

v=1.5×−20=−30