a point moves along a circle of radius 1m with speed v=at .The tangential acceleration of the point at a time when it has completed 1/8 of the revolution from start is ?
luckkyramyasist:
wat r u asking for ???
wtas u r question
he is asking acceleration read carefully
thanks for u r help
mntn nt :)
mine answer is coming π/4t²
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v = linear speed = a t
the linear tangential acceleration = dv/dt = a = constant at any time...
the centripetal acceleration = v² / R = a² t² / R
this depends on the time and continuously increases.
the linear tangential acceleration = dv/dt = a = constant at any time...
the centripetal acceleration = v² / R = a² t² / R
this depends on the time and continuously increases.
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