a point o inside a rectangle abcd is joined to the vertices.prove that the sum of the areas of a pair of opposite triangle so formed is equal to the sum of the areas of the other pair of triangles
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To prove: Area (∆AOD) + Area (∆BOC) = Area (∆AOB) + Area (∆COD)
Draw EOF ║ AB and LOM ║ AD
To prove: Area (∆AOD) + Area (∆BOC) = Area (∆AOB) + Area (∆COD)
Draw EOF ║ AB and LOM ║ AD
Now
From (i) and (ii),
Area (∆AOD) + Area (∆BOC) = Area (∆AOB) + Area (∆COD)
Draw EOF ║ AB and LOM ║ AD
To prove: Area (∆AOD) + Area (∆BOC) = Area (∆AOB) + Area (∆COD)
Draw EOF ║ AB and LOM ║ AD
Now
From (i) and (ii),
Area (∆AOD) + Area (∆BOC) = Area (∆AOB) + Area (∆COD)
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