A works twice as fast as B. They work together and complete a job in 8 days. How long would A take to complete the rest of the job.
Answers
Answered by
8
Now let us formulate this.
1/A + 1/B = 1/8 ……(Given)
1/X + 1/2X = 1/8
Taking LCM
2/2X + 1/2X = 1/8
3/2X = 1/8
2X/3 = 8
2X = 24
X = 12
So A will complete the work alone in 12 Days.
1/A + 1/B = 1/8 ……(Given)
1/X + 1/2X = 1/8
Taking LCM
2/2X + 1/2X = 1/8
3/2X = 1/8
2X/3 = 8
2X = 24
X = 12
So A will complete the work alone in 12 Days.
dharitri65:
your welcome
Answered by
7
GIVEN :-
A works twice as fast as B
They work together to complete job in 8 days.
TO FIND :-
Time taken by A to complete the job.
SOLUTION :-
Let A took 'x' days to complete the job.
Time taken by B = 2x days.
They work together and complete a job in 8 days.
(1/x) + 1/2x = 1/8
=> 3/2x = 1/8
=> 24 = 12x
=> x = 12
Hence, A takes 12 days to complete the job
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