Math, asked by dharitri65, 1 year ago

A works twice as fast as B. They work together and complete a job in 8 days. How long would A take to complete the rest of the job.

Answers

Answered by subham237
8
Now let us formulate this.

1/A + 1/B = 1/8 ……(Given)

1/X + 1/2X = 1/8

Taking LCM

2/2X + 1/2X = 1/8

3/2X = 1/8

2X/3 = 8

2X = 24

X = 12

So A will complete the work alone in 12 Days.


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Answered by KhataranakhKhiladi2
7

GIVEN :-

A works twice as fast as B

They work together to complete job in 8 days.

TO FIND :-

Time taken by A to complete the job.

SOLUTION :-

Let A took 'x' days to complete the job.

Time taken by B = 2x days.

They work together and complete a job in 8 days.

(1/x) + 1/2x = 1/8

=> 3/2x = 1/8

=> 24 = 12x

=> x = 12

Hence, A takes 12 days to complete the job

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