Question

A point object is moving on the ground at a
constant velocity of 10 m/s away from a plane
mirror which is placed at 90 degree to the
direction of the motion.Calculate the relative
velocity between the object and its image.​

Answer 1

Velocity of the objective relative to the image is given as

v

D

=

v

O

−

v

1

v

Ol

=(vcosθ

i

^

−vsinθ

j

^

)+(vcosθ

i

^

+vsinθ

j

^

)

⇒

v

D

=2vcosθ

i

^

⇒v

Ol

=2vcosθ

hope I can help u

MARK MY ANSWER AS BRAINLIEST ANSWER