Question

a point of an object is kept 10cm
away on the surface of a thick double convex lens of a refractive index 1.5 and radii of curvature 10 can and 8 cm central thickness of the lens is 2 cm determine location of the final image considering paraxial rays only ​

Answer 1

Answer:

In a double convex lens :-

Object distance, u = -10 cm

Refractive index, n = 1.5

Radius of curvatures, R1 = 10 cm

and R2 = -8 cm

Central thickness of the lens, t = 2 cm

To find: final image distance, “v” considering paraxial only

For thick convex lens, we haveFocal length, f is positive

R1 is positive

R2 is negative

Object distance “u” is negative and image distance “v” is positive

Image formed is real & inverted .

By lens maker’s formula now :-

1/f = [1.5-1][(1/10) + (1/8) - {(1.5 - 1)*2 / (1.5 * 10 * 8)}]

1/f = [0.5] [0.1 + 0.125 – (1/120)]

1/f = [0.5] [0.21667] = 0.108335

Now, as per the general lens formula, we have :-

1/f = 1/v - 1/u

0.108335 = 1/v – 1/(-10)

0.108335 – 0.1 = 1/v

= 0.008335

∴ v = 1/0.008335 = 119.97 cm ≈ 120cm

Hence, the location of the final image is 120 cm away from the lens considering paraxial only.

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Answer 2

Answer:

I hope this answer is 120 CM