A point of application of a force, F = 5i - 3j + 2k is moved from (2i + 7j + 4k) to (-5i + 2j + 3k). Find the work done.
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OP= 2i + 7j + 4k, OQ = - 5i + 2j + 3k
d = OQ - OP
d = - 7i - 5j - k
W = F. d
= (5i - 3j +2k). (- 7i - 5j - k)
= - 35 (i.i) + 15(j.j) - 2 (k.k)
= - 35 +15 - 2
= - 22
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