A point of charge 12 micro coulomb is located at the centre of a cube of side 1m calculate the electric flux through each face of the cube.
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q = 12×10^-6 C
So, the electric flux passing through the cube => ( formula shown in figure)
Electric Flux = (12×10^-6)/(8.854×10^-12)
Electric Flux = 1.35×10^6 N-m^2/C
Now, because a cube has 6 face, so the electric flux passing through one face =
= 1.35×10^6/6
= 0.226×10^6
= 2.26×10^5 N-m^2/C.....●
So, the electric flux passing through the cube => ( formula shown in figure)
Electric Flux = (12×10^-6)/(8.854×10^-12)
Electric Flux = 1.35×10^6 N-m^2/C
Now, because a cube has 6 face, so the electric flux passing through one face =
= 1.35×10^6/6
= 0.226×10^6
= 2.26×10^5 N-m^2/C.....●
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