Question

A point on a wheel rotates about its centre according to the relation theta = 6t – 2t^3 Find the
average angular velocity of a point on the wheel during a time in which it comes to rest
(in rad/s)​

Answer 1

Answer:

average angular velocity=4

Explanation:

given

theta=6t-2t^3

by differentiating theta

d theta/dt=d(6t-2t^3)/dt

w=6-6t

w=theta/t

6-6t=6t-2t^3/t

t(2t-6)=0

2t=6

t=3

average angular velocity=4

Answer 2

Explanation:

hope you UNDERSTOOD

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