Math, asked by GodReaper4756, 1 year ago

A point on the parabola y^2=18x at which the ordinate increases at twice the rate of the abscissa is

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Answered by Anonymous
9
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Answered by SushmitaAhluwalia
5

The point on the parabola is (9/8, 9/2)

  • Given,

       Rate of change of y = 2(Rate of change of x)

                  \frac{dy}{dt} = 2\frac{dx}{dt}

                  (\frac{dy}{dt} )/(\frac{dx}{dt} ) = 2

                  \frac{dy}{dx} = 2   --------------------------(1)

  • Given parabola,

                  y^{2} = 18x  ------------------------(2)

  • Differentiating on both sides with respect to x

                  2y\frac{dy}{dx} = 18(1)

                   y(2) = 9                                [ from (1)]

                   y = 9/2

  • Substituting y in (2), we get

                  (9/2)^2 = 18x

                   81/4 = 18x

                     x = 9/8                    

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