A rectangular block has a square base of area 49cm2 and its height is 8 cm.find its total surface area.
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Area of base = 49cm^2
l × b =49
since base is square l=b
l^2=49
l=7 cm
so total surface area= 2(lb+bh+hl)
= 2(7×7 + 7×8 + 8×7)
=2(49 + 56 +56)
=2(161)
=322 cm^2
l × b =49
since base is square l=b
l^2=49
l=7 cm
so total surface area= 2(lb+bh+hl)
= 2(7×7 + 7×8 + 8×7)
=2(49 + 56 +56)
=2(161)
=322 cm^2
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4
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