Physics, asked by sapnavjain6093, 1 year ago

A point on the rim of a wheel 3m in diameter has a linear velocity of 18m/s. the angular velocity of the wheel is

Answers

Answered by raveenasri1823
28
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Answered by CarliReifsteck
14

Given that,

Diameter = 3 m

Linear velocity = 18 m/s

We need to calculate the angular velocity of the wheel

Using formula of linear velocity

v=r\omega

\omega=\dfrac{v}{r}

Where, v = linear velocity

r = radius of wheel

\omega = angular velocity

Put the value into the formula

\omega=\dfrac{18}{1.5}

\omega=12\ rad/s

Hence, The angular velocity of the wheel is 12 rad/s.

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