find 31st term of an ap whose 11th term is 38 and 16th term is 73
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32
We know that,
a 11 = 38 so , a+ 10d =38
a16 = 73 , a+15d = 73
By equating them by elimination method we get d =7
Now substitute the vale of d in any of the eq.
We get a +10d=38
=>a +10[7] =38
=>a= -32
Now we should find out the 31st term so
=>a31=a +[n-1]d
=> -32 +30 * 7
=>-32+210
=178
Therefore,the 31st term is 178...
Hope this will help u ...
a 11 = 38 so , a+ 10d =38
a16 = 73 , a+15d = 73
By equating them by elimination method we get d =7
Now substitute the vale of d in any of the eq.
We get a +10d=38
=>a +10[7] =38
=>a= -32
Now we should find out the 31st term so
=>a31=a +[n-1]d
=> -32 +30 * 7
=>-32+210
=178
Therefore,the 31st term is 178...
Hope this will help u ...
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