Question

construct a triangle pqr with QR equal to 5.5 CM angle Q is equal to 60 degree and Angle are equal to 45 degree construct the circumcircle of the triangle drawn

Answer 1

We follow these steps to construct triangle PQR and circumcircle  ,  Where QR  =  5.5 cm and  Q  =  60  and  R  =  45

Step 1 :  Draw line QR  =  5.5 cm

Step 2 : Take any radius (  Less than half of QR )  and center Q draw an arc that intersect our line QR at "  A " now with same radius and center " A "  draw another arc that intersect previous arc at  " B " .

Step 3 :  Draw a line QX that is passing through " B " .

Step 4 : Take any radius (  Less than half of QR )  and center R draw a semicircle that intersect our line QR at "  C " now with same radius and center " C "  draw another arc that intersect semicircle at  " D " and again with same radius and center " D "  draw another arc that intersect semicircle at  " E " .

Step 5 :  With same radius and take center " D "  and " E " draw two arcs those intersect at " F " Now Join RF and line RF intersect our semicircle at " G " .

Step 6 :  With same radius and take center " C "  and " G " draw two arcs those intersect at " H "

Step 7 :  Draw a line RY that is passing through " H " 

Line QX and RY intersect at  " P "  , SO we get our triangle PQR . Now to draw circumcircle , we follow these steps

Step 8 : Take any radius (  More than half of PQ )  and take center " P "  and " Q " draw two arcs on both side of line PQ those arcs intersect at " I "  and " J " .

Step 9 : Take any radius (  More than half of PR )  and take center " P "  and " R " draw two arcs on both side of line PR those arcs intersect at " K "  and " L " .

Line " IJ " and " KL " intersect at " O " .

Step 10 :  Take center  " O "  and radius as length of " OQ "  draw a circle .