Question

A point on x - axis is at distance 13 from A(11, 12). Find the coordinates of P​

Answer 1

Answer:

Let the coordinates of point P(x, 0).

According to statement

AP = 13.

$\sqrt{ {(x - 11)}^{2} + {(0 - 12)}^{2} } = 13 \\ squaring \: both \: sides \\ {(x - 11)}^{2} + 144 = 169 \\ {(x - 11)}^{2} = 169 - 144 \\ {(x - 11)}^{2} = 25 \\ = > x - 11 = 5 \: or \: x - 11 = - 5 \\ x = 16 \: or \: 6$

So coordinates of P is (16, 0) and (6, 0)

Answer 2

Answer:

this is correct....................