a point on y-axis equidistant from a(1,4) and b(7,8) is
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distance formula= √(x1-x2)∧2 + (y1-y2)∧2
= √(1-7) ∧2 + (4-8)∧2
= √-6∧2 -8∧2
=√36-64
=√-28
=√-4(7)
=-2√7
∴ the point on y-axis is 2√7 .
hope this will help you
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