Question

A point P divides the line RT in the ratio -2:5. Find the coordinates of P given R(3,1) and T(6,-5)

Answer 1

Answer:

Ratio = -2:5

Using section formula

(m1x2+m2x1/m1+m2,m1y2+m2y1/m1+m2)

(-2*6+5*3/-2+5,-2*-5+5*1/-2+5)

(-12+15/3,10+5/3)

(3/3,15/3)

(1,5)=coordinates of P