Physics, asked by MiniDoraemon, 7 months ago

A point P moves in counter - clockwise direction on a circular path as shown in the figure . the movement of P is such that it sweeps out a length s = t³+5 , where s is in metre and t is in second . are radius of the path is 20m . the acceleration of P when t = 2s is nearly [ AIEEE 2010] ​

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Answered by shivam74086399
3

s =  {t}^{3}  + 5

v =  \frac{ds}{dt}  = 3 {t}^{2}

and    \: at =  \frac{dv}{dt}   = 6t

(at)t = 2 = 12

aR =v^2/R =(Vt=2)^2/R

a =    \sqrt{a \times \frac{2}{t} }  +  \sqrt{a \times \frac{2}{r} }  = 13.994

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