Question

A point P (x,y) is such that it's distance from the fixed point (a,0) is equal to it's distance from y-axis. Prove that the equation of the locus is y^2=a(2x-a)

Answer 1

Distance of the point P(x,y) from y-axis is x.
Distance of point P(x,y) from the point (a,0) is given by,
$\sqrt{ {(x - a)}^{2} + {y}^{2} }$
So by solving as in the pic,
you can find the locous.

Thanks.
Tripathy

Answer 2

Step-by-step explanation:

This is the answer of the question.

Hope you get your correct answer.