Math, asked by sami17, 1 year ago

find the area of an isosceles right triangle whose equal sides are 15 cm each

Answers

Answered by BrainlyHulk

323

hi friend

area of triangle=1/2*BH

= 1/2 *15*15=225/2=112.5cm2

sami17: Dear, read the question attentively, B is not equal to H

BrainlyHulk: hi

BrainlyHulk: in a isoceles triangle it is

BrainlyHulk: and should be right angled

BrainlyHulk: the hypotenuse is longer side

BrainlyHulk: then other two equal sides are b and h

NehaAdlakha: Srryy.....what r u saying

NehaAdlakha: I know b is not equal to h...but it is an isoceles triangle whose two sides are equal.....right

Answered by Cricetus

Given:

According to the question,

Base,

B = 15 cm

Height,

H = 15 cm

To find:

Area of isosceles triangle = ?

Solution:

As we know,

⇒ The area of isosceles triangle = $\frac{1}{2}\times Base\times Height$

On substituting the values, we get

⇒ = $\frac{1}{2}\times 15\times 15$

⇒ = $\frac{1}{2}\times 225$

⇒ = $112.5 \ cm^2$

Thus the area will be "112.5 cm²".

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