Question

A point source emits sound with a power output of 100 watts. What is the intensity (in W/m2) at a distance of 10.0 m from the source?

Answer 1

Explanation:

Power per unit area is intensity

as point source is given

area will be of sphere =4pie r²

= 4×3.14× 100

=1256m²

intensity = 100/1256

=0.079

Answer 2

The intensity of the point source is 0.079N/m².

Given:-

Power of the point source = 100W

Distance from the source = 10m

To Find:-

The intensity of the point source.

Solution:-

We can simply find out the intensity of the point source by following these simple steps.

As

Power of the point source (p) = 100W

Distance from the source (r) = 10m

The intensity of the point source (i) =?

Since it's a point source, it will create a sphere around it.

and According to the formula for the intensity

$intensity = \frac{power}{area}$

$i = \frac{p}{a}$

$i = \frac{p}{4\pi {r}^{2} }$

$i = \frac{100}{4×3.14 \times 10 \times 10}$

$i = \frac{1}{4×3.14}$

$i = 0.318×0.25$

Hence, The intensity of the point source is 0.079N/m².

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