Question

A point traverses half its distance with velocity v0. The remaining part of the distance was covered with velocity v1 for half the time and velocity v2 for the remaining half. The average velocity of the object for the whole journey is:
(1) 2v1(v0+v2)/(v0+2v1+2v2)
(2) 2v0(v0+v1)/(v0+v1+v2)
(3) 2v0(v1+v2)/(v1+v2+2v0)
(4) 2v2(v0+v1)/(v1+2v2+v2)

Answer 1

is tarah ka kam kiya hai is prakar hai jis tarah ek kabhi n khatm bhi

Answer:

fgrhsgzue the same as last year but AM flexible with dates and time for the delay email from you soon with some of these services are offered

Explanation:

refhsb you can get a new message by anyone other you can get a new i thi to vo bhi kam ho jati han aur is bar to man

Answer 2

Answer:

The average velocity of the object for the whole journey is  $\dfrac{2v_{0}(v_{1}+v_{2})}{v_{1}+v_{2}+2v_{0}}$

(3) is correct option.

Explanation:

Given that,

Velocity of point= v₀

Velocity of remaining part = v₁

Let s be the total distance traversed by the point and time t₁ the time taken to cover half the distance.

Further let 2t be the time to cover the rest half of the distance.

We need to calculate the time t₁

Using formula of distance

$\dfrac{s}{2}=v_{0}t_{1}$

$t_{1}=\dfrac{s}{2v_{0}}$.....(I)

We need to calculate the time 2t

Using formula of distance

$\dfrac{s}{2}=(v_{1}+v_{2})t$

$2t=\dfrac{s}{(v_{1}+v_{2})}$...(II)

We need to calculate the average velocity of the object for the whole journey

Using formula of average velocity

$v_{avg}=\dfrac{s}{t_{1}+2t}$

Put the value from equation (I) and (II) into the formula

$v_{avg}=\dfrac{s}{\dfrac{s}{2v_{0}}+\dfrac{s}{(v_{1}+v_{2})}}$

$v_{avg}=\dfrac{2v_{0}(v_{1}+v_{2})}{v_{1}+v_{2}+2v_{0}}$

Hence, The average velocity of the object for the whole journey is  $\dfrac{2v_{0}(v_{1}+v_{2})}{v_{1}+v_{2}+2v_{0}}$