Question

a pole 14 m high casts a shadow of 10m at the same time what will be the height of a tree the length of whose shadow is 7 meters in proportions method

Answer 1

Hey !!!

this is your answer.....

Given :- A pole of 14 m cats Shadow of 10 m.
We have to d find the length of that tree whose length of Shadow is 7m.

We know that larger the pole Wii be, larger the length of pole will be.
or smaller the pole, smaller will be its pole.

So, this is a case of direct proportion.
General formula for direct proportion
$= > \frac{x1}{y1} = \frac{x2}{y2}$
According to the question,
x1 = 14 m.
y1 = 10 m.
y2 = 7 m.

We have to obtain X2,

$= > \frac{14}{10} = \frac{x1}{7} \\ = > x1 = \frac{14 \times 7}{10} \\ = > x1 = \frac{98}{10} \\ = > x1 = 9.8$
Hence, the height of tree will be 9.8 metres.

Hope you got the answer......
If any doubt, feel free to ask.

Answer 2

Height of pole = 14 m

Length of shadow be 10 m

Than x = height of pole / length of shadow

Than x = 14 / 10 = 1.4

Now at the same time

Length of shadow of tree be 7m

Height of tree be hm

Than x = height of tree / length of shadow of tree

= 1.4 = h/7

= h= 9.8 m.