A pole 6 m high casts a shadow 2√ 3 m long on the ground, then the Sun’s elevation is
(A) 60° (B) 45° (C) 30° (D) 90°
Answers
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Answer:
Let height = 6m
length of shadow = 2√3m
ø is angle of elevation
Tanø= height/shadow length
= 6/2√3=√3
ø=π/3
Angle of elevation is =60°
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so the answer is option (a)60°
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