A pole 6m3ocm casts a shadow of 2m10cm.Find the length of pole whose shadow is 3m 20cm.
Answers
Answer:
960 cm
Step-by-step explanation:
Here, we can used the formula of direct and inverse proportion.
First of all, the all units will be same.
Either, m should be changed in cm or cm should be changed in m.
(I will prefer to change m into cm as it is easy)
6m 30cm = 1m=100cm
6m 30cm = 1m=100cm = 6m 30 cm= 6×100cm+30cm
6m 30cm = 1m=100cm = 6m 30 cm= 6×100cm+30cm = 6m 30 cm= 600 cm+30 cm
6m 30cm = 1m=100cm = 6m 30 cm= 6×100cm+30cm = 6m 30 cm= 600 cm+30 cm = 6m 30 cm= 630 cm
2m 10 cm= 210 cm
2m 10 cm= 210 cm3m 20 cm= 320 cm
Height of the pole = 630 cm x2
Height of the pole = 630 cm x2 Shadow casted = 210 cm 320 cm
Now, we can solve this by direct and inverse proportion.
It is a case of direct proportion as if the height of the pole is more, than shadow casted by the pole will be more.
x1/y1 = x2/y2
Here, we have to find x2. (x1=630 cm, y1=210 cm, y2=320 cm)
= 630cm/210cm =x2/320 cm
630cm/210cm =x2/320 cm= 630cm×320cm/210cm= x2
630cm/210cm =x2/320 cm= 630cm×320cm/210cm= x2= 960 cm=x2
So, a pole which has a height of 630 cm casts a shadow of 210 cm. If the length of shadow is 320 cm, then the height of pole is 960 cm.