Question

A pole casts a shadow of length 20√3m on the ground when sun's elevation is 60°. Find the height of pole

Answer 1

Step-by-step explanation:

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Answer 2

The height of the pole is 60m.

Step-by-step explanation:

Given:

• The length of the shadow = 20√3m
• The angle of elevation = 60°

To find:

• The height of the pole

Solution:

• The pole is standing upright, which means it is perpendicular to the shadow.

• Hence, the relation of tangent (tan) can be used here.

tan(angle of elevation) $=\frac{height of the pole}{length of the shadow}$

$tan 60 = \frac{height}{20\sqrt{3} }$

• The value of tan 60 is $\sqrt{3}$

Hence,

$\sqrt{3} = \frac{height}{20\sqrt{3} }$

$Height = \sqrt{3}\times {20\sqrt{3} }$

$Height = {3}\times {20}$

$Height = 60$

hence, the height of the pole is 60m.