A pole casts shadow of lenght 2root3 m on the ground, when the sun 's elevation is 60 degree. Find the height of the pole.
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Answered by
1
bc=2√3 and Ф=60° let ab be x
tanФ=ab/bc
tan60° =x/2√3
√3=x/2√3
∴x=6cm
Find the height of the pole. =6cm
tanФ=ab/bc
tan60° =x/2√3
√3=x/2√3
∴x=6cm
Find the height of the pole. =6cm
AbaAaliya:
pls mark it as the brainliest
Answered by
0
as per we can write that
h/2root3=root3
h=2×3
h=6m
h/2root3=root3
h=2×3
h=6m
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