A pole held vertically with one end on the ground.The length of the pole is 30 m.The pole is allowed to fall.Assuming that the lower end of the pole does not slip,with what velocity will the upper end strike the ground?
Answers
Answered by
6
In this question we will use Newtons equation of motion for a freely falling body.
The height from which the top of the rod falls is equivalent to the length of the rod.
Since we don't have the time, we will use the following equation of motion :
2gs = v² - u²
Where :
g is acceleration due to gravity and it is equal to 10m/s²
S is the distance covered which is equal to the length of the rod which is 30m
V is the final velocity
U is the initial velocity which is equal to 0 for a falling body.
Substituting the values in the formula :
2 × 10 × 30 = v² - 0
600 = v²
√600 = √v²
V = 24.49 m / s
The height from which the top of the rod falls is equivalent to the length of the rod.
Since we don't have the time, we will use the following equation of motion :
2gs = v² - u²
Where :
g is acceleration due to gravity and it is equal to 10m/s²
S is the distance covered which is equal to the length of the rod which is 30m
V is the final velocity
U is the initial velocity which is equal to 0 for a falling body.
Substituting the values in the formula :
2 × 10 × 30 = v² - 0
600 = v²
√600 = √v²
V = 24.49 m / s
Similar questions