A pole of 6m high casts a shadow 2√3 m long on the ground and then find sun's angle of elevation
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HEY FREIND....
height of a pole = 6 m
shadow of pole = 2√32√3
So, height/length of shadow = tan A
tanA=6/2√3tanA=6/2√3
tanA=3/√3tanA=3/√3
tanA=√3tanA=√3
So A = 6000
so angle of elevation is 600
height of a pole = 6 m
shadow of pole = 2√32√3
So, height/length of shadow = tan A
tanA=6/2√3tanA=6/2√3
tanA=3/√3tanA=3/√3
tanA=√3tanA=√3
So A = 6000
so angle of elevation is 600
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