Question

how do I solve 2x^2-32=0

Answer 1

Answer:

x=4,−4

Explanation:

You can factor out a 2 as the GCF.

2(x2−16)=0

x2−16 is the difference of perfect squares, which are (x−4)(x+4)

Therefore, you now have 2(x−4)(x+4).

To solve this quadratic means to find the roots of it (the points where the parabola will cross the x-axis).
x−4=0
x=4

and

x+4=0
x=−4

Therefore, x = -4, 4

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