Question

A pole of height 6m casts a shadow of 4m on the ground. At the same time,if a building casts a shadow of 28m. Find the height of the building

Answer 1

Answer:

Height of pole=AB=6 m

Length of shadow of pole =BC=4 m

Length of shadow of tower=EF=28 m

In △ABC and △DEF

∠B=∠E=90

∘

both 90

∘

as both are vertical to ground

∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)

∴△ABC∼△DEF by AA similarity criterion

We know that if two triangles are similar, ratio of their sides are in proportion

So, DEAB = EFBC⇒DE6= 28

4⇒DE=6×7=42 m

Hence the height of the tower is 42 m

Step-by-step explanation:

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