Question

A pole of length 10m cast a shadow 2m long on the ground. At the same time a tower casts a shadow of length 60m on the ground then find the height of tower.

Answer 1

Solution:-
Height of the pole H1, = 10 m
Length of the shadow of the pole, X1 = 2 m
Height of the tower = H2 m
Length of the shadow of the tower, X2 = 60 m
Since, if the two shadows cast, that will form two triangles which will be similar. Therefore, the ratio of their corresponding sides will be equal.
Therefore.
H1/H2 = X1/X2
10/H2 = 2/60
H2 = 600/2
H2 = 300 m
Hence the height of the tower is 300 m.  Answer.

Answer 2

Height of the pole H1, = 10 m

Length of the shadow of the pole, X1 = 2 m

Height of the tower = H2 m

Length of the shadow of the tower, X2 = 60 m

Since, if the two shadows cast, that will form two triangles which will be similar. Therefore, the ratio of their corresponding sides will be equal.

Therefore.

H1/H2 = X1/X2

10/H2 = 2/60

H2 = 600/2

H2 = 300 m

Hence the height of the tower is 300m