Math, asked by ac0hagarithi, 1 year ago

Two years ago,a man's age was three times the square of his son's age.in three years time,his age will be four times his son's age.find their present ages.

Answers

Answered by krishnamurthyg
2
Two years ago, a man's age was three times the square of his son's age.
In three years time, his age will be four times his son's age.
Find their present ages.
(m - 2) = 3(s - 2)^2
(m + 3) = 4(s + 3)
m = 29 and s = 5
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