Question

A pole stands erect on the ground . If the angle of elevation of the top of the pole from a point 90m away from the foot of the pole is 30, find the height of pole

Answer 1

Step-by-step explanation:

let ab be the tower and BC be the shadow

BC= 90m

according to the question,

AB/BC = tan30

= AB/90 = 1/√3

AB= 90/√3=30√3m

So height of the tower is 30√3 m