Question

A police jeep is chasing a culprit going on a moter bike. The motor bike crosses a turn at a speed of
72 km/h. The jeep follows it at a speed of 108 km/h, crossing the turn 10 seconds later than bike
(keeping constant speed). After crossing the turn, jeep acclerates with constant accleration 2 m/s2.
Assuming bike travels at constant speed, after travelling a distance 20x m. from the turn, the jeep
catches the bike. Where x is an integer. Find x.
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Answer 1

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11th

Physics

Motion in a Straight Line

Graphs in Relative Motion

A police jeep is chasing a ...

PHYSICS

A police jeep is chasing a culprit going on a motorbike. The motorbike crosses a turning at a speed of 72 km/h. The jeep follows it at a speed of 90 km/h, crossing the turning ten seconds later than the bike.

Assuming that they travel at constant speeds, how far from the turning will the jeep catch up with the bike?

December 27, 2019avatar

Aatif Aghav

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ANSWER

VP = 90 km/h = 25 m/s. VC = 72 km/h = 20 m/s.

In 10 sec culprit reaches at point B from A. Distance converted by culprit S=vt=20×10=200m.

At time t = 10 sec the police jeep is 200 m behind the culprit Time=

v

s

=

5

200

=40s. (Relative velocity is considered).

In 40 s the police jeep will move from A to a distance S, where S=vt=25×40=1000m=1.0km away. ∴ The jeep will catch up with the bike, 1km far from the turning

Answer 2

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◆ Answer -

Type your question...

11th

Physics

Motion in a Straight Line

Graphs in Relative Motion

A police jeep is chasing a ...

PHYSICS

A police jeep is chasing a culprit going on a motorbike. The motorbike crosses a turning at a speed of 72 km/h. The jeep follows it at a speed of 90 km/h, crossing the turning ten seconds later than the bike.

Assuming that they travel at constant speeds, how far from the turning will the jeep catch up with the bike?

December 27, 2019avatar

Aatif Aghav

SHARE

ANSWER

VP = 90 km/h = 25 m/s. VC = 72 km/h = 20 m/s.

In 10 sec culprit reaches at point B from A. Distance converted by culprit S=vt=20×10=200m.

At time t = 10 sec the police jeep is 200 m behind the culprit Time=

v

s

=

5

200

=40s. (Relative velocity is considered).

In 40 s the police jeep will move from A to a distance S, where S=vt=25×40=1000m=1.0km away. ∴ The jeep will catch up with the bike, 1km far from the turning

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