Question

A police moving on a highway with a speed of 30km/hr fires a bullet at a thief's car speeding away in the same direction with a speed of 192km/hr if the muzzel speed of the bullet is 150m/s the speed with which the bullet hit the theif's car is?

Answer 1

Speed of the police van, vp = 30 km/h = 8.33 m/s
Muzzle speed of the bullet, vb = 150 m/s
Speed of the thief’s car, vt = 192 km/h = 53.33 m/s
Since the bullet is fired from a moving van, its resultant speed can be obtained as:
= 150 + 8.33 = 158.33 m/s
Since both the vehicles are moving in the same direction, the velocity with which the bullet hits the thief’s car can be obtained as:
vbt = vb – vt
= 158.33 – 53.33 = 105 m/s

Answer 2

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Speed of the police van,

v(p) = 30 km/h = 8.33 m/s

Muzzle speed of the bullet,

v(b) = 150 m/s

Speed of the thief’s car,

v(t )= 192 km/h = 53.33 m/s

Since the bullet is fired from a moving van, its resultant speed can be obtained as: = 150 + 8.33 = 158.33 m/s

Since both the vehicles are moving in the same direction, the velocity with which the bullet hits the thief’s car can be obtained as: v(bt) = v(b) – v(t)= 158.33 – 53.33 = 105 m/s

I hope, this will help you

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