A polygon has 27 diagonal. How many side does it have?
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The formula to find the number of diagonals of a polygon with n sides is given by n(n-3)/2
We know that diagonals are 27
27=n(n-3)/2
27*2=n(n-3)
54=n^2-3n
n^2-3n-54=0
(n+6)(n-9)=0
n=-6
n=9
The no of sides cannot be -6 so the no of sides of a polygon having 27 diagonals are 9
Hope this answers helps you!!
We know that diagonals are 27
27=n(n-3)/2
27*2=n(n-3)
54=n^2-3n
n^2-3n-54=0
(n+6)(n-9)=0
n=-6
n=9
The no of sides cannot be -6 so the no of sides of a polygon having 27 diagonals are 9
Hope this answers helps you!!
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