Question

A polygon has 27 diagonals.What is the no. of sides of the polygon?

Answer 1

Answer:

9

Step-by-step explanation:

The number of diagonals in a polygon = n(n-3)/2 = 27

n(n-3) = 54

n²-3n - 54 = 0

(n - 9)(n+6) = 0

n = 9

sides = 9