A polygon has 27 diagonals.What is the no. of sides of the polygon?
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4
Answer:
9
Step-by-step explanation:
The number of diagonals in a polygon = n(n-3)/2 = 27
n(n-3) = 54
n²-3n - 54 = 0
(n - 9)(n+6) = 0
n = 9
sides = 9
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