A polygon has (n) sides and three of its exterior angles are 85, 76 and 46 the remaining (n-3) exterior angles are Each of 17, calculate the value of n.
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It is related to ANGLE PROPERTIES OF POLYGONS.
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Answer:
Polygon has 11 sides
Step-by-step explanation:
Sum of the exterior angles of any polygon is always 360 ∘
As three angles are 70 ∘ ,80 ∘ and 90 ∘ and remaining n − 3 angles are 15 ∘ and their sum is 360 ∘ ,we have
70+ 80 + 90 + 15 ( n − 3)= 360
or 15( n − 3 ) = 360 − 70 − 80 − 90 = 120
and n − 3 = 120 ÷15 = 8
i.e.
n = 11
Hence, polygon has
11 sides
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