a polygon has44 diagonals then find its sides
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Answered by
0
Answer:
11 sides
Step-by-step explanation:
n(n-3)/2 = 44
n(n-3) = 88 = 11(11-3)
n = 11 sides
Answered by
1
No. of angles
= no. of diagonals × 2
= 44 × 2 = 88
No. of diagonals
= ( n - 2 ) × 180
44 = ( n - 2 ) × 180
44 ÷ 180 = ( n - 2 )
11 ÷ 45 = ( n- 2 )
11 = 45 ( n - 2 )
11 = 45n - 90
45n = 11 + 90
45n = 101
n = 101 ÷ 45
= no. of diagonals × 2
= 44 × 2 = 88
No. of diagonals
= ( n - 2 ) × 180
44 = ( n - 2 ) × 180
44 ÷ 180 = ( n - 2 )
11 ÷ 45 = ( n- 2 )
11 = 45 ( n - 2 )
11 = 45n - 90
45n = 11 + 90
45n = 101
n = 101 ÷ 45
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