A polynomial p(x) is given as x^5 + kx^4 +4x^3 -x^2+5x-4. 1 is a zero of p( x ) Find k
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So as in the question it is given that 1 is the zero of p(x) therefore we will put the value of x in p(x) to calculate k we get-
(1)^5+k(1)^4+4(1)^3-(1)^2+5(1)-4=0
1+k+4+2+1=0
8+k=0
k=-8
Therefore the value of k is -8
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