Question

A polynomial p(x)p(x)p, left parenthesis, x, right parenthesis is given as x^5+kx^4+4x^3-x^2+5x-4x 5
+kx 4
+4x 3
−x 2
+5x−4x, start superscript, 5, end superscript, plus, k, x, start superscript, 4, end superscript, plus, 4, x, cubed, minus, x, squared, plus, 5, x, minus, 4.
111 is a zero of p(x)p(x)p, left parenthesis, x, right parenthesis.
Find k

Answer 1

Answer:

4x" (and any subsequent words) was ignored because we limit queries to 32 words.

Answer 2

k= -5

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