Question

(i) For an A.P., if a = 11 and d= 1.5, then t3 = ?
(A) 10 (B) 12 (C) 15 (D) 14​

Answer 1

Answer:

Step-by-step explanation:

a=11

d=1.5

n=3

T3=?

For 'n' terms in an AP

Tn=a+(n-1)d

T3=11+(3-1)(1.5)

T3=11+(2)(1.5)

T3=11+3

T3=14

Therefore,

                  The Third Term of the given AP is 14

Hope It Would Be Helpful!

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Answer 2

Option D - $t_3=14$

Step-by-step explanation:

Given : For an A.P., if a = 11 and d= 1.5.

To find : The value of $t_3$ ?

Solution :

The nth term of A.P is given by,

$t_n=a+(n-1)d$

Where, a=11 is the first term

d=1.5 is the common difference

n=3 is the number of terms

Substitute the value,

$t_3=11+(3-1)1.5$

$t_3=11+(2)1.5$

$t_3=11+3$

$t_3=14$

Therefore, the 3rd term is $t_3=14$.

So, option D is correct.

#Learn more

If the common difference is the A.P in which

T7=9 and T1.T2.T3 is least, is d Find d​

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