A polynomial p (x) when divided by x-1 gives remainder 1, when divided by x-2 gives remainder 2. What will be the remainder when p (x) is divided by (x-1)(x-2)
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By remainder theorem we have
p(1) = 1 , and , p(2) = 2
Let p(x) = (x-1)(x-2)*g(x) + ax + b , where g(x) is a polynomial not equal to 0
For x = 1 , p(1) = a(1) + b or 1 = a+b
For x = 2, p(2) = a(2) + b or 2 = 2a+b
Solving these two equations we have a = 1 and b = 0
Thus remainder is x
p(1) = 1 , and , p(2) = 2
Let p(x) = (x-1)(x-2)*g(x) + ax + b , where g(x) is a polynomial not equal to 0
For x = 1 , p(1) = a(1) + b or 1 = a+b
For x = 2, p(2) = a(2) + b or 2 = 2a+b
Solving these two equations we have a = 1 and b = 0
Thus remainder is x
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