Math, asked by arsh123randhawa, 1 month ago


A polynomial P(y) is given as ay^12+by^5-c , where a , b and c are natural numbers.
Is 0 a zero of p(y)​

Answers

Answered by Ranagehloch
1

Answer:

no, 0 is not a zero of this polynomial.

Step-by-step explanation:

for 0 to be a zero, p(0) needs to be equal to zero.

but p(0)=a(0)^12+b(0)^5-c

=-c

Since the result is not 0, therefore, 0 is not a zero of p(y)

Hope it helps

Answered by Sardrni
2

Answer

The number of zeroes of p(x) is the number of times the curve intersects the x-axis, i.e; attains the value 0.

Here, the polynomial p(x) meets the x-axis at 1 point.

So, number of zeroes =1...

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